integrands's Usage Examples:

be used for integrands having integer and/or fractional exponents.

Special cases of these reductions formulas can be used for integrands of the form (.

The integrands and the integrators are now stochastic processes: Y t = ∫ 0 t H s d X.

Gaussian quadrature for smooth integrands, but unlike Gaussian quadrature, tends to work equally well with integrands having singularities or infinite.

traditional algorithms for "well behaved" integrands, but are also effective for "badly behaved" integrands for which traditional algorithms may fail.

In the presence of a metric, it can be extended to continuous integrands via the Gauss–Bonnet theorem.

Tensor densities, especially integrands and variables of integration, may be allowed in manifestly covariant equations.

constraints, boundary contact angles, prescribed mean curvature, crystalline integrands, gravity, and constraints expressed as surface integrals.

the complexity of the integration problem in the worst-case setting for integrands of smoothness.

iterated integrals are equal to the corresponding double integral across its integrands.

elliptic integrands.

A different approach to the Reifenberg problem for elliptic integrands has been recently.

(non-analytic) integrands.

Also, Clenshaw–Curtis shares the properties that Gauss–Legendre quadrature enjoys of convergence for all continuous integrands f and.

This is possible because most numeric integrands are not polynomials (especially since polynomials can be integrated analytically).

Differential forms provide a unified approach to define integrands over curves, surfaces, solids, and higher-dimensional manifolds.

Thus this provides a method of extending the Itô integral to non adapted integrands.

} This is not the best approach for all integrands: another transformation may be appropriate, or one might prefer to break.

integrals on the right-hand side are the usual Riemann integral (the integrands are integrable because they are monotone in x {\displaystyle x} ).

lead to completely incorrect results, as the quadrature sum is (for most integrands of interest) highly ill-conditioned.

u}{\partial y}}=-{\frac {\partial v}{\partial x}}} We therefore find that both integrands (and hence their integrals) are zero ∬ D ( − ∂ v ∂ x − ∂ u ∂ y ) d x d.